4m^2+16m=-12

Solution for 4m^2+16m=-12 equation:

4m^2+16m=-12

We move all terms to the left:

4m^2+16m-(-12)=0

We add all the numbers together, and all the variables

4m^2+16m+12=0

a = 4; b = 16; c = +12;
Δ = b2-4ac
Δ = 162-4·4·12
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-8}{2*4}=\frac{-24}{8}
=-3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+8}{2*4}=\frac{-8}{8}
=-1
$